Question

The rate of the reaction in terms of the "disappearance of reactant" includes the change in the concentration of the reactant, the time interval, and the coefficient of the reactant. Consider the following reaction: 2A+3B→3C+2D The concentrations of reactant A at three different time intervals are given. Use the following data to determine the average rate of reaction in terms of the disappearance of reactant A between time = 0 s and time = 20 s. Time (s) 0 20 40 [A](M) 0.1200 0.0720 0.0540 Express your answer in molar concentration per second to three significant figures.

Answer 1

Answer:

The average rate of the reaction is 1.2 × 10⁻³ M/s

Explanation:

The rate of the reaction can be written in terms of the disappearance of reactant A. The average rate of the reaction is given by the variation of the concentration of reactant A over time divided by its stoichiometric coefficient:

average rate of reaction = - 1/2 * (final concentration - initial concentration)/time

Between 0 and 20 s, the average rate of the reaction is:

rate = - 1/2 ( 0.0720 M - 0.1200 M) / 20 s = 1.2 × 10⁻³ M/s