Question

We investigated a jet landing on an aircraft carrier. In a later maneuver, the jet comes in for a landing on solid ground with a speed of 115 m/s, and its acceleration can have a maximum magnitude of 8.97 m/s2 as it comes to rest.

a) From the instant the jet touches the runway what is the minimum time interval needed before it can come to rest?
b) Can this jet land at a small tropical island airport where the runway is 0.800 km long?
c) Explain your answer

Answer 1

Answer:

(a) It will take 12.82 sec to come into rest

(b) After calculation distance is 737.15 m which is less than 800 m so jet can land on the island

Explanation:

(a) When the jet lands at the ground its velocity is 115 m/sec

So initial velocity u = 0 m/sec

Finally jet will stop so its final velocity will be zero v = 0 m/sec

Maximum acceleration $a=8.97m/sec^2$

So minimum time, $v=u+at$

So $0=115-8.97\times t$

t = 12.82 sec

(b) Average speed $v=(\frac{u+v}{2})=(\frac{115+0}{2})=57.5m/sec$

Distance traveled in 12.82 sec = $d=57.5\times 12.82=737.15m$

As this distance is less than 800 m so jet can land on the island