Consider the series given below.
2, 6, 18, 54, ...
Given that the sum of the first n terms of the provided series is 6,560, determine the value of n.​

Respuesta :

Answer:

n = 8

Step-by-step explanation:

This is a geometric sequence where the sum to n terms is

[tex]S_{n}[/tex] = [tex]\frac{a(r^n-1)}{r-1}[/tex]

where a is the first term and r the common ratio

r = 6 ÷ 2 = 18 ÷ 6 = 54 ÷ 18 = 3 and a = 2, thus

[tex]\frac{2(3^n-1)}{3-1}[/tex] = 6560

[tex]\frac{2(3^n-1)}{2}[/tex] = 6560 ← cancel the 2

[tex]3^{n}[/tex]   - 1 = 6560 (add 1 to both sides )

[tex]3^{n}[/tex] = 6561

note that 6561 = [tex]3^{8}[/tex], hence

[tex]3^{n}[/tex] = [tex]3^{8}[/tex] ⇒ n = 8

Answer:

8

Step-by-step explanation:

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