Question

An opaque bag contains 5 green marbles, 3 blue marbles, and 2 red marbles. Two marbles are randomly drawn without replacement. P(2nd draw: blue | 1st draw: red)

A 1/5

B 3/10

C 2/9

D 1/3

Answer 1

Answer:

the first draw has a 20% chance of happening. the second has 33% chance of happening 33% of 20% is 6.6% in other word there is a 6.6% chance of u geting a red then a blue

Step-by-step explanation:

3 ÷ 9 = 1/3 or 0.3333333333333

Answer 2

Answer:  D. $\dfrac{1}{3}$

Step-by-step explanation:

Given : The number of blue balls in bag = 3

The number of red balls in the bag = 2

Total marbles =5+2+3=10

The probability of drawing first marbles as red :-

$\dfrac{\text{Number of red marbles}}{\text{Total marbles}}\\\\=\dfrac{2}{10}$

After this , the probability of drawing a blue marbles :-

$\dfrac{\text{Number of blue marbles}}{\text{Total marbles left}}\\\\=\dfrac{3}{9}=\dfrac{1}{3}$

i.e. $\text{P(2nd draw: blue }|\text{ 1st draw: red)}=\dfrac{1}{3}$