Answer:
CCl₂
Explanation:
Let us calculate the mass of carbon present in 100 grams of sample.
The formula to calculate the mass of carbon we can use the following formula.
[tex]\frac{12XmassofcarbondioxideX100}{44Xmassofsample}=\frac{12X1.37X100}{2.58x44}=14.5[/tex]
The mass of chlorine in the sample = 100-14.5 = 85.5g
Let us calculate the moles of each element:
moles of carbon = [tex]\frac{mass}{atomicmass}=\frac{14.5}{12}=1.208[/tex]
Moles of chlorine = [tex]\frac{mass}{atomicmass}=\frac{85.5}{35.5}=2.41[/tex]
The mole ratio is :
C:Cl = 1.208:2.41 = 1:2
So the empirical formula of the compound must be CCl₂