Answer:
He should plant 100 acres of corn and 400 acres of wheat.
Step-by-step explanation:
This problem can be solved by a siple system of equations.
]x denotes the number of acres of corn
y denotes the number of acres of wheat
Building the system:
The Johnson Farm has 500 acres of land allotted for cultivating corn and wheat. This means that:
[tex]x + y = 500[/tex]
The cost of cultivating corn and wheat (including seeds and labor) is $42 and $30 per acre, respectively. Jacob Johnson has $16,200 available for cultivating these crops. This means that:
[tex]42x + 30y = 16,200[/tex]
So, we have the following system
[tex]1) x + y = 500[/tex]
[tex]2) 42x + 30y = 16,200[/tex]
If he wishes to use all the allotted land and his entire budget for cultivating these two crops, how many acres of each crop should he plant?
[tex]1) x + y = 500[/tex]
[tex]2) 42x + 30y = 16,200[/tex]
I am going to write y as a function of x in 1), and replace in 2). So:
[tex]x + y = 500[/tex] means that [tex]y = 500-x[/tex]
[tex]42x + 30y = 16,200[/tex]
[tex]42x + 30(500-x) = 16,200[/tex]
[tex]42x + 15000 - 30x = 16,200[/tex]
[tex]12x = 1,200[/tex]
[tex]x = \frac{1,200}{12}[/tex]
[tex]x = 100[/tex]
Now, going back to 1:
[tex]y = 500 - x = 500 - 100 = 400[/tex]
He should plant 100 acres of corn and 400 acres of wheat.