Answer:19.32 m/s
Explanation:
Given
initial speed of car(u)=4.92 m/s
acceleration(a)=[tex]3.2 m/s^2[/tex]
Speed of car after 4.5 s
using equation of motion
v=u+at
[tex]v=4.92+3.2\times 4.5=4.92+14.4[/tex]
v=19.32 m/s
Displacement of the car after 4.5 s
[tex]v^2-u^2=2as[/tex]
[tex]19.32^2-4.92^2=2\times 3.2\times s[/tex]
[tex]349.05=2\times 3.2\times s[/tex]
s=54.54 m