Question

A metal ball of mass 100 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 2.5 kJ. Another metal ball of mass 200 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 5.0 kJ. What can be concluded from the data?

Answer 1

Explanation:

q = mCΔT

where q is heat,

m is mass,

C is specific heat capacity,

and ΔT is temperature change.

For the first ball:

2500 J = (100 g) C (90°C − 25°C)

C = 0.385 J/g/°C

For the second ball:

5000 J = (200 g) C (90°C − 25°C)

C = 0.385 J/g/°C

The two metals have the same specific heat, and are likely the same metal (possibly copper or zinc).

Answer 2

Answer:

( B )  The first ball is made of a material with a higher specific heat.

Explanation: