Question

Ship A is located 4.2 km north and 2.7 km east of ship B. Ship A has a velocity of 22 km/h toward the south and ship B has a velocity of 39 km/h in a direction 36 ° north of east. What are the (a) x-component and (b) y-component of the velocity of A relative to B?

Answer 1

Answer:

Explanation:

Given

Ship A has velocity of 22 Km/h

Ship B has velocity of 39 km/h towards 36 north of east

In vector form

$V_a=-22\hat{j}$

$V_b=39cos36\hat{i}+39sin36\hat{j}$

$V_{ab}=V_a-V_b$

$V_{ab}=-22\hat{j}-39cos36\hat{i}-39sin36\hat{j}$

$V_{ab}=-39cos36\hat{i}-(22+39sin36)\hat{j}$

Velocity x component $V_x=31.55 m/s$

Velocity of Y component $V_y=22+22.92=44.92 m/s$