Answer:
The planes´s horizontal distance is DH = 13845 meters
Explanation:
We need to get the vector components because we already know the distance and the angle so using the trigonometric identity of Cos(Ф) we can get the horizontal component and if we get the component on x axle like 22000 (m)*Cos(51°) = x so we can find that x = 13845.05 meters