Answer:
5430.85 square feet
Step-by-step explanation:
Height of the cylindrical part of the cilo = 25 feet
radius of the base cylindrical part of cilo = 8 feet
Now volume of cylindrical part of cilo =[tex]\pi r^{2} h[/tex]
Volume of cylindrical part of cilo = [tex]\pi(8^{2})25[/tex] = [tex]1600\pi square feet[/tex]
Now,
Height of the conical part of cilo = 6 feet
Radius of the conical part of cilo = 8 feet
Volume of the conical part of cilo = [tex]\frac{1}{3}\pi (8^{2})6[/tex]= [tex]128\pi square feet[/tex]
Volume of the entire cilo = [tex]1600\pi + 128\pi = 1728\pi[/tex]
since [tex]\pi =\frac{22}{7} therefore,[/tex]
volume of entire cilo = [tex]\frac{22}{7} (1728)[/tex]= 5430.85
