Question

A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow has a 7.20 m radius, at how many revolutions per minute are the riders subjected to a centripetal acceleration equal to that of gravity?

Answer 1

Answer:1.16 rad/s

Explanation:

Given

radius of circular path(r)=7.20 m

let $\omega$be the angular velocity of ride

and centripetal acceleration is given by $\omega ^2r$

which should be equal to gravity(g)

$\omega ^2r=g$

$\omega ^2=\frac{g}{r}$

$\omega =\sqrt{\frac{g}{r}}$

$\omega =\sqrt{1.3625}$

$\omega =1.16 rad/s$