Answer:
The normal force applied by block on the ground is (mg - F cosФ)
Explanation:
Lets explain how to solve the problem
At first you must distribute the force F into two components
Vertical component which is F cosФ
Horizontal component which is F sinФ
The block is in equilibrium, that means sum of forces acting on the
block is zero
So the upward forces equal the downward forces
Normal reaction force R applied by block on the ground and the
vertical component of F both are upward forces
The weight of the block is downward force
The normal reaction force R plus the vertical component of F is
equal to the weight
R + F cosФ = W
W = mg, where g is acceleration of gravity and m is the mass of
the block
R + F cosФ = mg
Subtract F cosФ from both sides
R = mg - F cosФ
The normal force applied by block on the ground is (mg - F cosФ)
