Question

Snowballs are thrown with a speed of 13 m/s from a roof 7.0 m above the ground. Snowball A is thrown straight downward; snowball B is thrown in a direction 25o above the horizontal. When the snowballs land, is the speed of A greater than, less than, or the same speed of B? Verify your answer by calculation of the landing speed of both

Answer 1

Answer:

Speed of both the ball will be same

Explanation:

For snow ball A

Initial velocity u = 13 m/sec

Acceleration due gravity $g=9.8m/sec^2$

According to third law of motion

$v^2=u^2+2gh$

So $v^2=13^2+2\times 9.8\times 7$

v = 17.5 m/sec, here v is final velocity

For snow ball B

Initial velocity v = 13 m/sec

Angle with horizontal = 25°

Horizontal component of velocity $u_x=ucos\Theta =13\times cos25^{\circ}=11.782m/sec$

Vertical component of velocity

$v_y^2=u_y^2+2gh$

$v_y^2=(usin\Theta )^2+2gh$

$v_y^2=(13sin25^{\circ})^2+2\times 9.8\times 7=167.3844$

$v_y=12.93m/sec$

So resultant velocity of ball B $V=\sqrt{v_x^2+v_y^2}=\sqrt{11.78^2+12.93^2}=17.5m/sec$

So speed of both the ball will be same

Answer 2

We have that for the Question"When the snowballs land, is the speed of A greater than, less than, or the same speed of B?" it can be said that  speed of both balls are equal

From the question we are told

Snowballs are thrown with a speed of 13 m/s from a roof 7.0 m above the ground. Snowball A is thrown straight downward; snowball B is thrown in a direction 25 above the horizontal. When the snowballs land, is the speed of A greater than, less than, or the same speed of B? Verify your answer by calculation of the landing speed of both

Generally the equation for the motion  is mathematically given as

v^2=u^2+2gh

Therefore

v^2=13^2+2*29.8*7

v=17.5m/s

Ball B

Horizontal  component of velocity

vy^2=uy^2+2gh

Therefore

vy^2=(usin\theta)^2+2gh

vy=12.9m/s

Hence

Resultant velocity

V=\sqrt{vx^2+vy^2}

V=\sqrt{11.78^2+12.93^2}

V=17.5m/s

Therefore

it can be said that the speed of both balls are equal

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