Answer:
15.76°
Explanation:
Hi!
Let C~ = A~ + B~
Then
C~ dot A~ = |C| |A| cos Ф
C~ dot A~ = (A~ + B~) dot A~ = |A|^2 + |B| |A| cos(120)
Therefore
cos Ф = (|A| + |B| cos(120)) / |C| = 15.65/|C|
and
|C|^2 = |A|^2 + |B|^2 + 2 |B| |A| cos(120)
|C| = 16.261
cos Ф = 15.65/16.261
Ф = 15.76°