Answer: 0.0034
Step-by-step explanation:
Given : The distribution of SAT scores (combining mathematics and reading) was approximately Normal with [tex]\mu=1003[/tex] and [tex]\sigma=220[/tex]
let x be the random variable that represents the SAT scores.
Using formula [tex]z=\dfrac{x-\mu}{\sigma}[/tex], the value of z corresponding to 1600 will be :-
[tex]z=\dfrac{1600-1003}{220}=\dfrac{597}{220}\approx2.71[/tex]
By using the standard normal table , we have
The proportion of SAT scores were actually higher than 1600 will be :-
[tex]P(z>2.71)=1-P(z\leq2.71)\\\\=1- 0.9966358=0.0033642\approx0.0034[/tex]
Hence, the proportion of SAT scores for the combined portions were reported as 1600 = 0.0034