Question

When methane reacts with oxygen, the products are carbon dioxide (CO2) and water (H2O). How many grams of water are formed if 24g of methane react completely with 96g of oxygen to form 66g of carbon dioxide? (include units)

Answer 1

Answer:

54 g

Explanation:

To solve this problem we will simply follow the Law of conservation of mass.

According to this law:

" The mass of product in the chemical reaction must be equal to the mass of reactant"

Given data:

mass of methane= 24 g

mass of oxygen= 96 g

mass of carbon dioxide= 66 g

mass of water= ?

Solution:

CH4 + 2O2 → CO2 +2H2O

24g + 96 g = 66 g + ?

120 g = 66 g + ?

120 g - 66 g = 54 g

so 54 g of waters are produce.

We can see that mass of water is equal to the sum of masses of reactant minus mass of product formed i.e mass of carbon dioxide.

Answer 2

Based on the mass ratio of the reaction, 54 g of water was produced.

What is the mass ratio of a reaction?

The mass ratio of a reaction is ratio of how masses of reactants combine products.

The equation of the reaction is given below:

• CH4 + 2 O2 → CO2 +2 H2O

From the equation of the reaction, 16 g of methane reacts with 64 g of water to produce 36 g of water and 44 g of carbon dioxide

mass ratio of carbon dioxide to water = 36/44

mass of water produced = 36/44 × 66

mass of water produced = 54 g

Therefore, 54 g of water was produced.

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