Question

Please help me. I will give brainliest.

Answer 1

Hey!

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Points:

(-2, 3) and (3, 0)

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Find the slope:

$= \frac{y2 - y1}{x2 - x1} \\=\frac{0 - 3}{3 - (-2)}\\= \frac{-3}{5} or -0.8$

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Slope Intercept Form:

y = mx + b

m = slope

b = y-intercept

Slope = -3/5

Y-intercept = 9/5

Answer: y = -3/5 + 9/5

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Point Slope Form:

y - y1 = m(x - x1)

You can use either of the points.

Answer:

y - 3 = -3/5(x - 2)

          or

y - 0 = -3/5(x - 3)

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Hope This Helped! Good Luck!

Answer 2

Answer:  The point slope form of the equation of graphed line is $ y-0=-\dfrac{3}{5}(x-3).$ and the slope-intercept form is $y=-\dfrac{3}{5}x+\dfrac{9}{5}.$

Step-by-step explanation:  We are given to find the point-slope form and slope-intercept form of the equation of the graphed line.

We know that

the slope of a line passing through the points (a, b) and (c, d) is given by

$m=\dfrac{d-b}{c-a}.$

From the graph, we note that the line passes through the points (3, 0) and (-2, 3).

So, the slope of the line is

$m=\dfrac{0-3}{3-(-2)}=-\dfrac{3}{5}.$

Sine the line passes through the points (3, 0), so its equation point-slope form is given by

$y-0=m(x-3)\\\\\Rightarrow y-0=-\dfrac{3}{5}(x-3).$

And, the slope-intercept form is

$y=-\dfrac{3}{5}(x-3)\\\\\\\Rightarrow y=-\dfrac{3}{5}x+\dfrac{9}{5}.$

Thus, the point slope form of the equation of graphed line is $ y-0=-\dfrac{3}{5}(x-3).$ and the slope-intercept form is $y=-\dfrac{3}{5}x+\dfrac{9}{5}.$