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A clothing business finds there is a linear relationship between the number of shirts, n ,it can sell and the price, p , it can charge per shirt. In particular, historical data shows that 5000 shirts can be sold at a price of $ 57 , while 15000 shirts can be sold at a price of $ 7 . Give a linear equation in the form p = m n + b that gives the price p they can charge for n shirts.

Respuesta :

Answer:

The equation that gives the price p they can charge for n shirts is

p = -0.005n + 82

Explanation:

Establish the variables for the equation

n = number of shirts that can sell

p = price per shirt

For case one we have n1 = 5000 p1 =$57

For case two we have n2 = 15000 p2= $7

Calculate the slope remeber that [tex]m=\frac{y2-y1}{x2-x1}[/tex] in this case the y will be represented by the price (p) and the x by the number (n) so we have:

m = [tex]m= \frac{p2-p1}{n2-n1} = \frac{7-57}{15000-5000} = \frac{-50}{10000}=   \frac{-5}{1000} =-0.005[/tex]

Replace in the equation (y-y1) = m (x - x1) with our variables:

(p-p1) = m(n-n1)

p - 57 = -0.005 (n - 5000)

p - 57 = -0.005n + 25

p = -0.005n + 25 + 57

p = -0.005n + 82

To verify we can replace for example the values of n2 to get p2 as follows

p= -0.005 (15000) + 82

p = - 75 + 82

p = 7

If fulfills the condition that for 15000 shirts the price is $ then the equation is correct

Answer:

p = -0.005n + 82

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