Answer:
First option
Fifth option
Step-by-step explanation:
Given the following function:
[tex]f(x) = 1 + x[/tex]
We can rewrite it in this form:
[tex]y = 1 + x[/tex]
Let's substitute each ordered pair shown in the options into the function:
First option [tex](1, 2)[/tex]
Since:
[tex]x=1\\y=2[/tex]
We get:
[tex]2 = 1 + 1\\2=2[/tex]
Second option [tex](3, 3)[/tex]
Knowing that:
[tex]x=3\\y=3[/tex]
We get:
[tex]3= 1 + 3\\3\neq4[/tex]
Third option [tex](0, 2)[/tex]
Knowing that:
[tex]x=0\\y=2[/tex]
We get:
[tex]2= 1 + 0\\2\neq1[/tex]
Fourth option [tex](1, 0)[/tex]
Since:
[tex]x=1\\y=0[/tex]
We get:
[tex]0 = 1 + 1\\0\neq2[/tex]
Fifth option [tex](0, 1)[/tex]
Since:
[tex]x=0\\y=1[/tex]
We get:
[tex]1 = 1 + 0\\1=1[/tex]
Therefore the ordered pairs [tex](1, 2)[/tex] and [tex](0, 1)[/tex] are for the given function [tex]f(x) = 1 + x[/tex]
