Answer:
Pressure, P = 18.68 pascals
Explanation:
Number of ball bearings, n = 145
Initial speed of ball bearings, u = 399.5 m/s
As the ball bearings collide head on and elastically. So,
Final speed of the ball bearings, v = -399.5 m/s
Mass of the ball bearing, m = 6.1 g
Time, t = 0.808 min = 48.48 s
We need to find the the pressure exerted on the material. Let it is equal to P. Mathematically, it is given by :
[tex]P=\dfrac{F}{A}[/tex]
Since, F = ma and [tex]a=\dfrac{v-u}{t}[/tex]
[tex]P=\dfrac{m(v-u)}{tA}[/tex]
For n number of ball bearings.
[tex]P=\dfrac{mn(v-u)}{tA}[/tex]
[tex]P=\dfrac{6.1\times 10^{-3}\times 145\times (399.5-(-399.5))}{48.48\times 0.78}[/tex]
P = 18.68 pascals
So, the pressure exerted on the material is 18.68 pascals. Hence, this is the required solution.