Two bodies, with heat capacities C₁ and C₂ (assumed independent of temperature) and initial temperatures T₁ and T₂ respectively, are placed in thermal contact. Show that their final temperature [tex]T_f[/tex] is given by T₁ = (C₁T₁ + C₂T₂)/(C₁ + C₂). If C₁ is much larger than C₂ . show that [tex]T_f[/tex] = T₁ + C₂(T₂ -T₁)/C₁.

Respuesta :

Explanation:

Given:

  • Initial Temperature of the body(1) with heat capacity [tex]C_1[/tex] is [tex]T_1[/tex]
  • Initial Temperature of the body(2) with heat capacity [tex]C_2[/tex] is [tex]T_2[/tex]

The heat lost by one body will be equal to the heat gained by other body by first law of thermodynamics.

Let assume that  [tex]T_1[/tex] is greater than [tex]T_2[/tex] and [tex]T_f [/tex] be the final temperature of both body.

[tex]C_1(T_1-T_f)=C_2(T_f-T_2)\\T_f=\dfrac{C_1T_1+C_2T_2}{C_1+C_2}\\[/tex]

If [tex]C_1[/tex] is much larger than [tex]C_2[/tex] then final temperature   [tex]T_f [/tex] will be

[tex]T_f=T_1+\dfrac{T_2C_2}{C_1}[/tex]