Respuesta :
Answer:
The answer is c)The two blocks end in a tie
Explanation (See attachment):
Let´s solve the general problem:
The hill is an inclined plane. We know there is no friction and no air resistance.
Let´s solve by using Energy equations and energy conservation law. At the top of the hill when the block is not moving it has a Potential Energy, as soon as it starts moving, all that Potential Energy starts converting to Kinetic Energy until it reaches the end of the hill:
1) At the top of the inclined plane we have a block of mass "m" with potential energy of [tex]Ep = mgh[/tex], where "m" is mass, "g" is gravity acceleration and "h" is height.
2) Just an instant before the block hits the bottom, it has a Kinetic Energy of [tex]Ek = \frac{1}{2} mv^{2}[/tex] where "m" is mass, and "v" is velocity
Thanks to energy conservation law we know that Ep = Ek:
- [tex]mgh = \frac{1}{2} mv^{2}[/tex]
- [tex]v = \sqrt{2gh}[/tex]
As we can see in our last equation, mass cancels out. This means that mass does not play a role in how fast this object slides down the inclined plane.
In conclusion, it doesn´t matter how much mass or how heavy the block is, it is going to slide down at the exact same velocity in a frictionless slide and without air resistance. This means, a 1lb block and a 100lb block will reach the bottom of the hill at the same time.
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