Respuesta :

Answer:

Infinity

Step-by-step explanation:

Apl[tex]\lim_{x \to \infty} \frac{4x^3 + 2x^2 +3x}{-9x^2 +5x +5} = \frac{inf}{inf}[/tex]

Which is undefined. In order to solve this, we divide and multiply the function by [tex]x^3[/tex] (which is the same as multipliying by 1).

[tex]\lim_{n \to \infty} \frac{4 + 2x^-1 +3x^-2}{-9x^-1 +5x^-2 +5x^-3} =  \frac{4}{0} = inf[/tex]

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