Answer:
The probability that our guess is correct = 0.857.
Step-by-step explanation:
The given question is based on A Conditional Probability with Biased Coins.
Given data:
P(Head | A) = 0.1
P(Head | B) = 0.6
By using Bayes' theorem:
[tex]P(B|Head) = P(Head|B) \times \frac{P(B)}{P(Head)}[/tex]
We know that P(B) = 0.5 = P(A), because coins A and B are equally likely to be picked.
Now,
P(Head) = P(A) × P(head | A) + P(B) × P(Head | B)
By putting the value, we get
P(Head) = 0.5 × 0.1 + 0.5 × 0.6
P(Head) = 0.35
Now put this value in [tex]P(B|Head) = P(Head|B) \times \frac{P(B)}{P(Head)}[/tex] , we get
[tex]P(B|Head) = P(Head|B) \times \frac{P(B)}{P(Head)}[/tex]
[tex]P(B|Head) = 0.6 \times \frac{0.5}{0.35}[/tex]
[tex]P(B|Head) = 0.857[/tex]
Similarly.
[tex]P(A|Head) = 0.857[/tex]
Hence, the probability that our guess is correct = 0.857.