HELP ASAP PLZ
A student is given that y varies directly with x^2 and that x = 2 when y = 8. Correct the student’s claim that x = 3 when y = 9 then. Explain your reasoning.

Respuesta :

Answer:

see explanation

Step-by-step explanation:

Given that y varies directly with x² then the equation relation them is

y = kx² ← k is the constant of variation

To find k use the condition x = 2 when y = 8

k = [tex]\frac{y}{x^{2} }[/tex] = [tex]\frac{8}{4}[/tex] = 2

y = 2x² ← equation of variation

When y = 9, then

2x² = 9 ( divide both sides by 2 )

x² = [tex]\frac{9}{2}[/tex] = 4.5 ( take the square root of both sides )

x = [tex]\sqrt{4.5}[/tex] ≈ 2.12 ≠ 3