Answer:
The answer to your question is: 1.48 x 10 ²⁴ particles of H₂SO₄
Explanation:
Data
density = 1.2 g/cm³
V = 2.00 x 10² ml
density = m / v
Then
mass = density x volume
mass = 1.2 x 200
mass = 240 g
MW H₂SO₄ = (1x2) +(32x1)+(16x4) = 98 gr
98 g of H₂SO₄ ------------------ 1 mol
240 g ------------------ x
x = 240 x 1 / 98 = 2.45 mol
Finally
1 mol ------------------- 6.023 x 10²³ particles
2.45 mol -------------- x
x = 2.45 x 6.023 x 10²³ / 1 = 1.48 x 10 ²⁴