Answer:
90
12
0.0154
Step-by-step explanation:
a) #Possible experimental run=#Temp x #pres x #cat=3x5x6=90
b) #Possible experimental run=(Temp. lowest) x 2.pres x #cat=1x2x6=12
c) C="different catalyst is used on each run"
In the first, I can choice 6 of 6 catalysts, in the second 5 of 6,...
then: P(C) = 6/6 x 5/6 x 4/6 x 3/6 x 2/6 x 1/6 = 5/324 = 0.0154