Respuesta :
Answer:
a0=2
a1=3
a2=2
a3=4
Explanation:
The balanced equation for the complete combustion of methane is:
2CH₃OH₍l₎ + 3O₂₍g₎ → 2CO₂ + 4H₂O₍l₎
This way, there is an equal number of atoms of each kind on both reactants side and the products side.
Therefore the coefficients represented by the unknowns are:
a0=2
a1=3
a2=2
a3=4
The above is the equation for the complete combustion of methanol.
Answer:
To find the number of atoms of each element we multiply coefficient × subscript
For example [tex]5 Ca_1 Cl_2[/tex] contains
5 × 1 = 5 ,Ca atoms and
5 × 2 = 10, Cl atoms
If there is a bracket in the chemical formula
For example [tex]3Ca_3 (P_1 O_4 )_2[/tex] we multiply coefficient × subscript × number outside the bracket.......... to find the number of atoms (Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )
So 3 × 3 = 9, Ca atoms
3 × 1 × 2 = 6, P atoms
3 × 4 × 2 = 24, O atoms are present.
Let us balance the equation
[tex]CH_3OH + O_2 > CO_2 + H_2O[/tex] (Unbalanced)
Reactant Side # of atoms of each element Product Side
1 C 1
4 H 2
3 O 3
Multiplying CH3OH by 2 we will have 2 - C, 8 - H and 6 - O on the reactant side so the equation changes to
[tex]2CH_3OH + O_2 > CO_2 + H_2O[/tex] (Unbalanced)
Reactant Side # of atoms of each element Product Side
2 C 1
8 H 2
4 O 3
By multiplying [tex]CO_2[/tex] by 2 and [tex]H_2 O[/tex] by 4 we will have
[tex]2CH_3OH + O_2 >2 CO_2 +4 H_2O[/tex] (Unbalanced)
Reactant Side # of atoms of each element Product Side
2 C 2
8 H 8
4 O 8
To balance O atoms on the left we multiply O_2 by 3
[tex]2CH_3OH + 3O_2 >2 CO_2 +4 H_2O[/tex] (balanced)(Answer)
Reactant Side # of atoms of each element Product Side
2 C 2
8 H 8
8 O 8
Balanced!!!
