In two or more sentences explain how to balance the chemical equation and classify its reaction type
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Answer:
Balancing is making the number of atoms of each element same on both the sides (reactant and product side).
To find the number of atoms of each element we multiply coefficient × subscript
For example [tex]5 Sr Cl_2[/tex] contains
5 × 1 = 5 ,Sr atoms and
5 × 2 = 10, Cl atoms
If there is a bracket in the chemical formula
For example [tex]3Sr_3 (P_1 O_4 )_2[/tex] we multiply coefficient × subscript × number outside the bracket.......... to find the number of atoms (Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )
So 3 × 3 = 9, Sr atoms
3 × 1 × 2 = 6, P atoms
3 × 4 × 2 = 24, O atoms are present.
Let us balance the equation
[tex]C_5 H_5 +Fe >Fe(C_5 H_5 )_2[/tex] (Unbalanced)
Reactant Side # of atoms of each element Product Side
1 Fe 1
5 C 10
5 H 10
We see here C and H are not balanced on the reactant side so we multiply [tex]C_5H_5[/tex] by 2 in order to get 10 that is, 2 times 5 =10 so now we have
[tex]2C_5 H_5 +Fe >Fe(C_5 H_5 )_2[/tex]
Reactant Side # of atoms of each element Product Side
1 Fe 1
10 C 10
10 H 10
The Equation is Balanced !!!!! as there are same number of atoms of each element on both the sides.
Balanced!!!