Question

An airplane flies from City A in a straight line to City B, which is 120 kilometers north and 180 kilometers west of City A. How far does the plane fly? (Round your answer to the nearest kilometer.)

Answer 1

Answer: 216 kilometers

Step-by-step explanation:

You need the hypotenuse, this is the formula: h = √(a^2 + b^2)    

so...

√(120^2 + 180^2)

√(14400 + 32400)

√46800

216.33

Answer 2

Pythagoras theorem are used to determine the missing side length of a right-angled triangle where the two sides are known. The airplane flown a distance of 216 km

The question is illustrated with the attached image. From the attached figure, we have:

$BO = 180km$

$AO = 120km$

The distance the plane fly is represented with AB.

Using Pythagoras theorem, we have:

$AB^2 = BO^2 + AO^2$

$AB^2 = 180^2 + 120^2$

$AB^2 = 32400 + 14400$

$AB^2 = 46800$

Take square roots

$AB = 216.33$

Approximate to the nearest kilometer

$AB = 216$

Hence, the plane flies a distance of 216 km

Read more about Pythagoras theorem at:

https://brainly.com/question/343682