Question

1. After a skydiver jumps from a plane, the only force initially acting on the diver
is Earth's gravitational attraction. After about ten seconds of falling, air
resistance on the diver will have increased so that its magnitude on the diver is
now equal in magnitude to Earth's gravitational force on the diver. At this
time, a diver in a belly-down position will be falling at a constant speed of
about 190 km/h.​

Answer 1

Answer:

See attachment

Explanation:

Missing question in the original text:

a) Draw a free-body diagram of the skydiver when the diver initially leaves the plane.

b) Draw a free-body diagram of the skydiver at the tenth  second of the falling

The free-body diagrams of the two situations can be found in the attached figure.

A free-body diagram is a diagram representing all the forces acting on a body. In this situation, we have:

- In part a), only the force of gravity is acting on the skydiver, and it acts downward. Its magnitude is (mg), where m is the mass of the skydiver and g is the acceleration of gravity. So, there is only one arrow representing the gravitational force, acting downward.

- In part b), there is also the air resistance, which acts in opposite  direction (upward) to the motion of the skydiver, and it is labelled with R. Since the skydiver at the tenth second is falling at a constant speed, its acceleration must be zero, and this means that the net force acting on him is zero: so, the two forces (air resistance and gravity) must be equal in magnitude and in opposite direction, therefore they are represented as two arrows of equal length and opposite direction.