Answer:
8.4 ml of water is needed to make a 10 ml of a 2x concentration.
Explanation:
From question,
[tex]M1= 5M,[/tex]
[tex]M2= 400mM \times 2 (2 \times solution) =0.8M,[/tex]
[tex]V2= 10ml[/tex]
[tex]V1= \frac{(M2 \times V2)}{M1}[/tex]
This gives [tex]V1 = 1.6 ml[/tex]
V1 is the available volume of water in the stock solution.
To obtain 10ml of 2x concentration, the volume of water required is: [tex]10-1.6 =8.4ml[/tex]of water.
Hence 8.4 ml of water is needed to make a 10 ml of a 2x concentration.