Answer:
28 gallons
Step-by-step explanation:
We are given that a sports car gets 14mpg in city driving and 19mpg for highway.
The model G=[tex]\frac{1}{14} c+\frac{1}{19 }h[/tex]
Where G=Amount of gasoline used (in gal) for c miles driven in the city and h miles driven on the high way.
Amount of gas used in 14 miles car in the city driving=1 gal
Amount of gas used in 1 mile car in the city driving=[tex]\frac{1}{14} gal[/tex]
Amount of gas used in c miles car in the city driving =[tex]\frac{1}{14}c[/tex] gal
Similarly, for car driving on highway
Amount of gas used in h miles for car driving on highway=[tex]\frac{1}{19}h[/tex]
c=98 miles in the city
h=399 miles on the highway
We have to find the amount of gas used required to derive 98 miles in the city and 399 miles on the highway.
Substitute the value of c and h in the given expression
Then, G=[tex]\frac{1}{14}\times 98+\frac{1}{19}\times 399=7+21=28 gal[/tex]
Hence, the amount of gas required to derive 98 miles in the city and 399 miles on the highway=28 gallons
Answer:
Evaluate the expression for the given values of the variables. Under selected conditions, a sports car gets 14 mpg in city driving and 19 mpg for highway driving. The model G = 114c + 119h represents the amount of gasoline used (in gal) for c miles driven in the city and h miles driven on the highway. Determine the amount of gas required to drive 98 mi in the city and 399 mi on the highway.
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