An arithmetic sequence is given by adding a common difference to a first term continuously
The 67th term of the sequence 6, 13, 20, 27, is 468
The reason why the value of the 67th term is correct is given as follows;
The given arithmetic sequence is 6, 13, 20, 27
The first term of the sequence is a₁ = 6
The common difference, d, is found as follows;
d = 27 - 20 = 20 - 13 = 13 - 6 = 7
The nth, aₙ, term of an arithmetic sequence is given as follows;
aₙ = a₁ + (n - 1)·d
Therefore;
The 67th term (n = 67) is, a₆₇ = 6 + (67 - 1)·7 = 468
The 67th term is 468
Learn more about arithmetic sequence here:
https://brainly.com/question/19916647
