Respuesta :
Answer:
14.7 m/s
Explanation:
During a crash, a car moving with some initial velocity comes to rest. This means the car undergoes a constant deceleration. So according to the question, we have
Given:
- v = final velocity of the car = 0 m/s
- a = acceleration of the car = [tex]-50g = -50\times 9.8\ m/s^2 = -490\ m/s^2[/tex]
- t = time for which the crash occurs = 30 ms = 0.03 s
Let us assume that the maximum initial velocity of the car for which the driver still could survive on a crash be u.
During the crash, the car moves with a constant acceleration. so using the equation for a constant acceleration, we have
[tex]v = u+at\\\Rightarrow u = v-at\\\Rightarrow u = 0-(-490)(0.03)\\\Rightarrow u =14.7[/tex]
Hence, the highest speed that the car could have had such that the driver survived is 14.7 m/s.
Answer:
The highest speed is 14.7 m/s
Explanation:
According to the data that the exercise gives, we have the following:
a = acceleration = -50*g
t = 30 ms = 0.03 s
if we use the equation:
v = u + a*t, where v = 30
replacing values and clearing u:
u = (50 * 9.8)*0.03 = 14.7 m/s