Respuesta :
Answer:
a) 176.45
b) 141.2
Explanation:
output 7,200
productivity: 0.12 van per labor hour
340 laborer employed
Where:
productivity = outpt/base
0.12 = 7,200/labor hours
7,200 / 0.12 = 60,000 total labor hours
Then we divide by the total laborers to know the average per laborer.
60,000/340 = 176.46 = 176.45 hours
(B) if the productivity increases to 0.15
then:
7,200/0.15 = 48,000
48,000 / 340 = 141.17 = 141.2
The average number of hours worked per laborer is 176.5 hours and when productivity is increased the average number of hours worked per laborer is 141.2 hours.
What is Productivity?
Generating a measure used to measure how well an organization (or individual, industry, country) effectively transforms inputs (workers, building materials, machinery, etc.) into goods and services. This is usually expressed in terms of output inputs.
As per the given information, In December, General Motors manufactured 7,200 customized vans for its factory in Detroit. The production of staff at the facility is known to have been 0.12 vans per hour of work per month. 340 factory workers were hired that month.
A) It is estimated that each worker produces 0.10 vans per hour:
[tex]\rm\,Productivity =\dfrac {Units\,produced}{Labour\,hours}\\\\= 0.12 = \dfrac {7,200}{Labour\,hours}\\\\= 60,000\,labour\,hours.\\\\Average\,number\,of \,hours = \dfrac{Total\,labour\,hours}{Total\,number\,of\,labourers}\\\\= \dfrac{60,000}{340}\\\\= 176.5 hours.[/tex]
B) Labor productivity increases to 0.15 vans per hour per job:
[tex]\rm\,Productivity =\dfrac {Units\,produced}{Labour\,hours}\\\\= 0.15 = \dfrac {7,200}{Labour\,hours}\\\\= 48,000\,labour\,hours.\\\\Average\,number\,of \,hours = \dfrac{Total\,labour\,hours}{Total\,number\,of\,labourers}\\\\= \dfrac{48,000}{340}\\\\= 141.2\,hours.[/tex]
Hence, The average number of hours worked per laborer is 176.5 hours and when productivity is increased the average number of hours worked per laborer is 141.2 hours.
To learn more about productivity, refer to the link:
https://brainly.com/question/1151291