[tex]\bf \cfrac{7+2(5-9)^2}{(4+1)^2-3(2^2)}\implies \cfrac{7+2(\stackrel{\downarrow }{-4})^2}{(\underset{\uparrow }{5})^2-3(\underset{\uparrow }{4})}\implies \cfrac{7+2(\stackrel{\downarrow }{16})}{\underset{\uparrow }{25}-3(4)}\implies \cfrac{7+\stackrel{\downarrow }{32}}{25-\underset{\uparrow }{12}} \\\\\\ \cfrac{39}{13}\implies \cfrac{3}{1}\implies 3[/tex]
recall PEMDAS, parentheses or groups first, from innermost to outermost, then exponents and so on.
