Respuesta :
Answer:
A) [tex]V=62 i + 0 j + 0 k[/tex]
B) [tex]X=0.93 km[/tex]
Explanation:
A) In this situation we are talking about a car moving only in the X- axis, hence the velocity of the car is:
[tex]V=62 i + 0 j + 0 k[/tex]
Where the unit vectors [tex] i [/tex], [tex] j [/tex] and [tex] k [/tex] represent the components [tex] x [/tex], [tex] y [/tex] and [tex] z [/tex] in the cartesian plane.
In this sense, each unit vector is defined to have a magnitude of exactly one (1).
B) Velocity is defined as the variation of position in time, if this car is moving only along the x direction we will have:
[tex]V=\frac{X}{t}[/tex]
Clearing the position:
[tex]X=V.t[/tex]
[tex]X=(62 km/h)(0.015 h)[/tex]
[tex]X=0.93 km[/tex]
The distance travelled by a object is the product of its velocity and the time taken to cover the distance.
- A)The expression for the velocity of the car, using the speed v and the unit vectors i ,j, and k is,
[tex]V=62\hat i+0\hat j+0\hat k[/tex].
- B)The x-component of the position vector, in units of kilometers, at time t=0.015 hr is 0.93 km.
What is constant speed?
Constant speed is the speed by which a body travelled same distance for each interval of time.
Given information-
The constant speed of the car is 62 km/h.
Positive x-axis is pointed in the direction of the motion of the car.
The origin is fixed at some point on the road.
- A) The expression for the velocity of the car, using the speed v and the unit vectors i ,j, and k-
The constant speed of the car is 62 km/h in x-axis
As the car is moving in he x-axis direction of the Cartesian coordinate system. Thus the y-axis and z-axis are zero.
The expression can be given as,
[tex]V=62\hat i+0\hat j+0\hat k[/tex]
Here, [tex]\hat i ,\hat j, \hat k[/tex] are the components as unit vector of the [tex]x,y,z[/tex] in respectively in the Cartesian coordinate system.
- B) The x-component of the position vector, in units of kilometers, at time t=0.015 hr
The distance travelled by a object is the product of its velocity and the time taken to cover the distance.
Here the velocity of the body is 62 km/h and time is 0.0015 hr. Thus the distance travelled can be given as,
[tex]x=62\times0.015\\x=0.93\rm km[/tex]
Hence,
- A)The expression for the velocity of the car, using the speed v and the unit vectors i ,j, and k is,
[tex]V=62\hat i+0\hat j+0\hat k[/tex].
- B)The x-component of the position vector, in units of kilometers, at time t=0.015 hr is 0.93 km.
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