Answer:
a) 647 kN/C
b) -71.9 kN/C
Explanation:
Using Gauss law relating electric flux to the charge contained inside a surface we arrive at this equation for the electric field around a infinite charged line:
E = ρ / (2 * π * r * e0)
The electric field on the XY plane will be the sum of the electric fields caused by both lines:
E(y) = ρ1 / (2 * π * (y - Y1) * e0) + ρ2 / (2 * π * (y - Y2) * e0)
With
Y1 = 0 (the position in Y where the first line is)
Y2 = 0.4
e0 = 8.85*10^-12
ρ1 and ρ2 are the charges per unit of length of the lines
At point y = 0.2
E(0.2) = 4.8*10^-6 / (2 * π * (0.2) * 8.85*10^-12) -2.4*10^-6 / (2 * π * (0.2 - 0.4) * e8.85*10^-12) = 647 kN/C
At point y = 0.6
E(0.6) = 4.8*10^-6 / (2 * π * (0.6) * 8.85*10^-12) -2.4*10^-6 / (2 * π * (0.2 - 0.6) * e8.85*10^-12) = -71.9 kN/C