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Answer:

0.000077713

0r

7.7713 x 10^-5

The value of the expression [tex]\left (\dfrac{8\times 4 \times 2}{8\times 7} \right )^2 \times \left (\dfrac{8^0}{7^{-3}} \right )^{-3} \times 7^{-9}[/tex] is equivalent to 64/49.

What is the exponent?

Exponent is defined as the method of expressing large numbers in terms of powers.

The given expression is;

[tex]\left (\dfrac{8\times 4 \times 2}{8\times 7} \right )^2 \times \left (\dfrac{8^0}{7^{-3}} \right )^{-3} \times 7^{-9}[/tex]

The expression is equivalent to the given expression and is determined in the following steps given below.

[tex]=\left (\dfrac{8\times 4 \times 2}{8\times 7} \right )^2 \times \left (\dfrac{8^0}{7^{-3}} \right )^{-3} \times 7^{-9}\\\\= \dfrac{8^2}{7^2} \times \dfrac{1}{7^{-9}} \times 7^{-9}\\\\= \dfrac{8^2}{7^2}\\\\=\dfrac{64}{49}\\\\[/tex]

Hence, the value of the expression [tex]\left (\dfrac{8\times 4 \times 2}{8\times 7} \right )^2 \times \left (\dfrac{8^0}{7^{-3}} \right )^{-3} \times 7^{-9}[/tex] is equivalent to 64/49.

Learn more about exponents here;

https://brainly.com/question/11789078

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