Respuesta :
Answer:180
Step-by-step explanation: Well, since the two angles are a linear pair, they are supplementary or add up to 180 degrees.
measure of angle EFG + measure of angle GFH = 180
(33N + 1616) + (55N + 2828) = 180
combining like terms, 88N + 4444 = 180
Solving for N results in N = (180 - 4444)/88 = -4264/88 = -533/11 = -48 and 5/11 or -48.454545....
This improper fraction of -533/11 ironically turns out to be quite helpful.
Substituting this value into the expressions above produce the following angles.
Angle EFG = 33N+1616 = 33(-533/11)+1616 = 1616 - 33*533/11 <-- property/definition of subtraction
= 1616 - 3*533 <-- because 33 and 11 cancel out
= 1616 - 1599 <-- order of mixed operations; PEMDAS
Likewise, yep
Angle GFH = 55(-533/11)+2828 = 2828 - 55*533/11
= 2828 - 5*533 <-- becuase 55 and 11 cancel out
= 2828 - 2665
= 163
Notice that the sum of these angles are in fact 17 + 163 = 180
Answer:
m∠EFG = 114°
m∠GFH = 66°
Step-by-step explanation:
It is given in the question
m∠EFG = 5n + 24
and m∠GFH = 3n + 12
Since both the angles ∠EFG and ∠GFH are linear pair.
Therefore, m∠EFG + m∠GFH = 180°
Now we plug in the measures of the given angles
(5n + 24) + (3n + 12) = 180
(5n + 3n) + (24 + 12) = 180
8n + 36 = 180
8n = 180 - 36
8n = 144
[tex]n=\frac{144}{8}[/tex]
n = 18
Since m∠EFG = 5n + 24
m∠EFG = 5×18 + 24
= 90 + 24
= 114°
m∠GFH = 3n + 12
= 3×18 + 12
= 54 + 12
= 66°