Answer:
The acceleration of the car is [tex]3.13 m/s^2[/tex]
Explanation:
In the question it is given that car initially heads north with a velocity [tex]15 m/s[/tex]. It then accelerates for [tex]4.25 s[/tex] and in the end its velocity is [tex]28.3 m/s[/tex].
initial velocity [tex]u = 15 m/s[/tex]
time [tex]t=4.25 s[/tex]
final velocity [tex]v=28.3 m/s[/tex]
The equation of acceleration is
[tex]a= \frac{(v-u)}{t}[/tex]
[tex]= \frac{(28.3-15)}{4.25} = \frac {13.3}{4.25} =3.13m/s^2[/tex]
The value of acceleration is positive, here since the car is speeding up. If it was slowing down the value of acceleration would be negative.
