Question

How do you solve 4b^2+8b+7=4 using the quadratic formula

Answer 1

$4b^2+8b+7=4$

Quadratic equation formula:

For a quadratic equation  of the  form $ax^2+bx+c=0$
the solution are:

$x_1,2= \frac{-b \frac{+}{-} \sqrt{b^2-4*a*c} }{2*a}$

for a = 4 , b = 8 , c = 3

$b_1,2= \frac{-8 \frac{+}{-} \sqrt{8^2-4*4*3} }{2*4}$

$b= \frac{-8+ \sqrt{8^2-4*4*3}}{2*4} =- \frac{1}{2}$

$b= \frac{-8- \sqrt{8^2-4*4*3} }{2*4} = -\frac{3}{2}$

The final solutions to the quadratic equation are:

$b= -\frac{1}{2} ,b=- \frac{3}{2}$

hope this helps!