Question

The speed of sound in dry air at 20 °C is 343.5 m s-1, and the frequency of the sound from the note C# above middle C on the piano is 277.2 s-1(according to the American standard pitch scale). Calculate the wavelength of the sound and the time it will take to travel 49.2 m across a concert hall. Wavelength = (answer) m

Answer 1

Answer:

1.23917 m

0.14323 s

Explanation:

v = Speed of sound in dry air at 20 °C = 343.5 m/s

f = Frequency of note C# = 277.2 /s = 277.2 Hz

λ = Wavelength

$v=f\lambda\\\Rightarrow \lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{343.5}{277.2}\\\Rightarrow \lambda=1.23917\ m$

Wavelength = 1.23917 m

Distance the wave needs to travel is 49.2 m

Time = Distance / Speed

$\text{Time}=\frac{49.2}{343.5}=0.14323\ s$

Time taken for the sound to travel across the concert hall is 0.14323 s

Answer 2

The wavelength of the sound will be 1.23917 m. While the time it will take to travel 49.2 m across a concert hall will be 0.14323 sec.

What is wavelength?

The wavelength is defined as the length between two successive troughs or crests. The wavelength is also the span between two points in a wave with the exact change phase.

The given data in the problem is

c is the Speed of sound in dry air at 20 °C = 343.5 m/s

f is the Frequency of note C# = 277.2 /s = 277.2 Hz

λ is the  Wavelength=?

f is the wave's frequency= 277.2 Hz

t is the time period=?

d is the distance traveled by the wave= 49.2 m

The association between the  wavelength, frequency, and speed is given as

wavelength = speed of light/frequency

$\rm \lambda=\frac{c}{f} \\\\\rm \lambda=\frac{343.5}{277.2} \\\\\rm \lambda=1.23917\;m.$

As we know the relation between distance and time

$\rm time = \frac{distance}{speed} \\\\\rm time = \frac{49.2}{343} \\\\\rm time =0.14323 \;sec.$

Hence the time it will take to travel 49.2 m across a concert hall will be 0.14323 sec.

To learn more about the wavelength refer to the link;

brainly.com/question/7143261