Answer: 0.0080
Step-by-step explanation:
Given : The manufacturer's website states that the average weight of each stick is [tex]\mu=2.25[/tex] oz with a standard deviation of [tex]\sigma=0.17[/tex] oz.
We assume the weight of the drumsticks is normally distributed.
Using formula [tex]z=\dfrac{x-\mu}{\sigma}[/tex], the z-value corresponds x=2.66 will be :-
[tex]z=\dfrac{2.66-2.25}{0.17}\approx2.41[/tex]
By using the standard normal distribution table for z, we get
P-value = [tex]P(z\geq2.41)=1-P(z<2.41)[/tex]
[tex]\\\\=1-0.9920237=0.0079763\approx0.0080[/tex]
Hence, the probability of the stick's weight being 2.66 oz or greater=0.0080