Question

A​ heavy-duty shock absorber is compressed 4 cm from its equilibrium position by a mass of 700nbspkg. How much work is required to compress the shock absorber 4 cm from its equilibrium​ position? (A mass of 700 kg exerts a force​ (in newtons) of 700​g, where galmost equals9.8 m divided by s squared​.)Set up the integral that should be used to find the work required to compress the shock absorber 4 cm from its equilibrium position. Use decreasing limits of integration. Express all displacements in meters.

Answer 1

The work required to compress the shock absorber is 274.4 J.

The given parameters:

• Displacement, x = 4 cm
• Mass of the shock absorber, m = 700 kg
• Applied force, F = 700g

Work done

The work required to compress the shock absorber is calculated as follows;

$W = Fx\\\\W = (700g) \times x\\\\W = (700 \times 9.8) \times 0.04\\\\W = 274.4 \ J$

Thus, the work required to compress the shock absorber is 274.4 J.

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