Respuesta :

Answer:

[tex]3x^3-19x^2+17x+4[/tex]

Step-by-step explanation:

For this one, all we need to do is multiply. A couple things to note:

  1. You can't add numbers with different powers of x (you can't add x with x^2)
  2. When multiplying numbers with different powers of x together, you add those powers (x^1*x^2 = x^3)

So let's multiply:

[tex](3x - 4)(x^2 - 5x - 1)\\3x^3-15x^2-3x-4x^2+20x+4\\3x^3-15x^2-4x^2-3x+20x+4\\3x^3-19x^2+17x+4[/tex]

Our answer is [tex]3x^3-19x^2+17x+4[/tex]

Note* standard form just means we have the highest power first (x^3 before x^2)

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