In the diagram, RT bisects ∠SRQ, and m∠QRT = 55°. Find m∠SRQ.
![In the diagram RT bisects SRQ and mQRT 55 Find mSRQ class=](https://us-static.z-dn.net/files/d51/01455c7af52861d8204c6844027afab0.jpg)
Answer:
∠SRQ = 110°
Step-by-step explanation:
Since RT bisects ∠SRQ, then
∠SRT= ∠QRT - 55° and
∠SRQ = ∠SRT + ∠QRT = 55° + 55° = 110°