Answer:
The area of the sandbox is 32 ft^2
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The area of a rectangle is equal to
[tex]A=LW[/tex]
where
L is the length of rectangle
W is the width of rectangle
we have
[tex]L=10-2=8\ ft[/tex] ----> difference of the x-coordinates
[tex]W=12-8=4\ ft[/tex] ----> difference of the y-coordinates
substitute
[tex]A=(8)(4)=32\ ft^2[/tex]
therefore
The area of the sandbox is 32 ft^2
